files / problems / landau-legendre / compute / q3 / README.md

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Landau 3 / Legendre, third computation

Outcome

Assume RH. For every real x≥1x\geq1 and every

δ≥450488039838720000000000000=0.22524401991935,\delta\geq\frac{4504880398387}{20000000000000} =0.22524401991935,

the interval [x2+δ,(x+1)2+δ][x^{2+\delta},(x+1)^{2+\delta}] contains a prime. This tightens q1's certified threshold 0.225250.22525. It does not prove Legendre's conjecture and does not extend the finite Oppermann record.

Replay

From any directory, run

problems/landau-legendre/compute/q3/run_all.sh

The replay uses Python 3 and a standard C compiler, needs no network, and writes only to a temporary directory. It first rechecks q1's exact certificate for the previous threshold, regenerates the q3 certificate, byte-compares it with the committed copy, reconstructs every rational enclosure independently, and runs a separate long double calculation.

Why the extra digits are real

Put

N=70,500,000,000,000,d=0.22524401991935,α=2+d,X=N2/α.N=70{,}500{,}000{,}000{,}000,\qquad d=0.22524401991935,\qquad \alpha=2+d,\qquad X=N^{2/\alpha}.

For 2<α<32<\alpha<3, Taylor's theorem gives, for x>0x>0,

(x+1)α−xα>αxα−1+α(α−1)2xα−2.(x+1)^\alpha-x^\alpha >\alpha x^{\alpha-1} +\frac{\alpha(\alpha-1)}2x^{\alpha-2}.

Consequently, Chamberland--Straub inequality (6) follows if

S(x)=xd/2+α−12xd/2−1−1αx−α/2−2225log⁡x>0.S(x)=x^{d/2}+\frac{\alpha-1}{2}x^{d/2-1} -\frac1\alpha x^{-\alpha/2}-\frac{22}{25}\log x>0.

Their simpler condition (5) drops the last two power terms. At the splice x=Xx=X, its certified logarithmic margin is negative: its exact upper bound is less than −2.03⋅10−13-2.03\cdot10^{-13}. Thus q1's one-term test does not certify this new value.

Write A=Xd/2=Nd/αA=X^{d/2}=N^{d/\alpha} and b=(α−1)/2b=(\alpha-1)/2. At XX, the ratio of the retained correction to AA is

t=bX−1αNA.t=\frac bX-\frac1{\alpha N A}.

The rational certificate proves 2⋅1012<X<2.8⋅10122\cdot10^{12}<X<2.8\cdot10^{12} and 25<A<2625<A<26, then obtains an exact lower bound for tt. Using log⁡(1+t)≥t/(1+t)\log(1+t)\geq t/(1+t) gives a positive strengthened overlap margin greater than 1.51⋅10−141.51\cdot10^{-14}.

For x≥Xx\geq X, differentiation gives

xS′(x)=d2xd/2−2225−b(1−d2)xd/2−1+12x−α/2.xS'(x)=\frac d2x^{d/2}-\frac{22}{25} -b\left(1-\frac d2\right)x^{d/2-1} +\frac12x^{-\alpha/2}.

The same coarse bounds prove this is greater than 1.931.93. Hence SS is increasing after the splice. The analytic argument covers x≥Xx\geq X, while the published finite Oppermann result and Chamberland--Straub Proposition 3.4 cover x<Xx<X. The exponent-transfer argument from q1 covers every larger δ\delta.

Certificate

certs/rh_delta_taylor.json contains normalized rational enclosures for all logarithms and every sign used above. No decimal approximation is trusted by the authoritative verifier.