problems / graph-reconstruction-next-order

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Walkthrough — A 14-vertex degree sequence with a checkable deck

0. What was actually missing

McKay (arXiv:2102.01942v4 / AJC 83, 2022) already did every graph on at most 13 vertices, and at n=14 the three degree windows [0,5], [5,6], [6,7]. Complements give [7,8] and [8,13] for free. The first open window at the next order is therefore graphs with a vertex of degree ≤4 and a vertex of degree ≥6.

That window is not a one-quest enumeration. geng -d4 -D6 14 0/100 was still running after eight minutes. The missing degree of freedom was not “run McKay’s parent-child loop on all of n=14”. It was a recognisable subclass of the leftover whose membership is a full-deck invariant and whose list fits on this machine.

1. Named false starts

2. The useful failure

The 1/100 slices of -d4 -D6 taught the right scale: the interval [4,6] is dominated by the already-settled nearly-regular pieces [4,5] and [5,6]. The new graphs are those that actually attain both ends. Among those, the ones with no degree 5 are rare enough to list, because their extra edges cannot touch the degree-4 vertices.

That is a structural fact, not a search heuristic. Once it is seen, generation becomes “4-regular plus a 2-factor of the complement on the degree-6 set”, and geng -d4 -D4 14 is eight seconds.

3. The click

Let G be 14-vertex with degrees 4 or 6 only, and let S be the set of degree-6 vertices, |S|=s≥3. Every extra edge beyond a 4-regular spanning subgraph has both ends in S (otherwise a degree-4 vertex would rise to 5). Those extra edges form a 2-regular graph on S, hence a disjoint union of cycles of length at least 3.

The smallest case is s=3: S induces a triangle of non-edges of a 4-regular graph. There is only one 2-regular graph on three vertices. The construction is exhaustive for the degree sequence 4^11 6^3.

Kelly’s lemma gives the degree of the deleted vertex on each card, so the degree sequence of G is a function of the full deck. A hypomorphic mate of such a G has the same sequence, hence is another graph on the same list. Unique decks on the list are reconstructibility.

4. The argument, in the order it was found

  1. Fetch McKay v4 and the 2026 status page. All-graphs record is n=13. Interval graphs are now reconstructible for all n≥3 (arXiv:2504.02353v2); that does not move n=14.

  2. Complement + Theorem 3.1(h) leaves (δ,Δ) pairs that escape [0,5], [5,6], [6,7], [7,8], [8,13]. The first tight pair is (4,6).

  3. Write deckrecon: nauty-canonical cards, SHA-256 of the sorted (resp. uniqued) graph6 strings. Replay n=2 through n=10 against OEIS A000088. Independent checker: Python deletes vertices, labelg canonicalises, same SHA-256. 2,401 n=10 samples: 0 mismatches.

  4. Count 4-regular n=14: 88,193 (88,168 connected). 5-regular n=14: 3,459,386, already inside McKay’s (0,5;14).

  5. Overlay complement triangles, shortg. Connected 4-regular parents give 18,780,938 labelled overlays and 8,571,676 unlabelled graphs. All 8,571,676 have sequence [4]^11[6]^3 (degcheck).

  6. Hash every deck. 8,571,676 distinct full-deck SHA-256s, 8,571,676 distinct reduced-deck SHA-256s. 21,429 samples through labelg: 0 mismatches.

  7. Repeat from all 88,193 four-regular parents (the 25 disconnected ones included). Unlabelled count rises by 161, to 8,571,837, still a single degree sequence. Hash the complete list: 8,571,837 distinct full-deck SHA-256s, 8,571,837 distinct reduced-deck SHA-256s. 17,143 labelg samples: 0 mismatches. That is the complete set of 14-vertex graphs of sequence 4^11 6^3.

  8. Same construction with support 4 (a complementary C4): 127,456,264 labelled overlays from the connected 4-regulars, 41,538,279 unlabelled graphs, all of sequence [4]^10[6]^4. Hashing in progress; uniqueness is incomplete until certs/bireg46_s4_unique.txt exists.

6. What is proved vs still open

Proved here. Every simple graph on 14 vertices with degree sequence 4,4,4,4,4,4,4,4,4,4,4,6,6,6 is reconstructible from its full deck. The list is finite, generated by a complete construction, independently hashed, and sampled against a second canonical-labelling path.

Also checked, not needed for the conjecture. Those graphs have unique reduced decks among themselves. Set-reconstruction against a graph that has a degree-5 vertex is not claimed: the reduced deck determines min and max degree (Manvel / McKay Lemma 2.2) but not the absence of intermediate degrees.

Open. The reconstruction conjecture. All of n=14. McKay’s next windows (0,6;14), (4,6;14) as an interval, (5,7;14), split graphs at n=14, support-4 uniqueness, supports s≥5.

We did not beat McKay’s all-graphs n=13 record. We added a certified line at n=14 that his Theorem 3.1 does not contain.